2014
07-31
07-31
ajax请求页如何真正返回json数据 NEW
$r = $db->query("SELECT title, thumb ,description , contentid FROM ".DB_PRE."content WHERE catid =2165 AND status = 99 AND thumb !='' ORDER BY contentid DESC limit 0,2");/*while($s = $db->fetch_array($r)){$data[]=array('contentid'=>...
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